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3(2x+1)=-3(2x-2)-5x
We move all terms to the left:
3(2x+1)-(-3(2x-2)-5x)=0
We multiply parentheses
6x-(-3(2x-2)-5x)+3=0
We calculate terms in parentheses: -(-3(2x-2)-5x), so:We get rid of parentheses
-3(2x-2)-5x
We add all the numbers together, and all the variables
-5x-3(2x-2)
We multiply parentheses
-5x-6x+6
We add all the numbers together, and all the variables
-11x+6
Back to the equation:
-(-11x+6)
6x+11x-6+3=0
We add all the numbers together, and all the variables
17x-3=0
We move all terms containing x to the left, all other terms to the right
17x=3
x=3/17
x=3/17
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