3(3k+6)+3(k-12)=66

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Solution for 3(3k+6)+3(k-12)=66 equation: 



3(3k+6)+3(k-12)=66

We move all terms to the left:

3(3k+6)+3(k-12)-(66)=0

We multiply parentheses

9k+3k+18-36-66=0

We add all the numbers together, and all the variables

12k-84=0

We move all terms containing k to the left, all other terms to the right

12k=84

k=84/12

k=7

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