15t2-26t-8=0

Solution for 15t2-26t-8=0 equation:

15t^2-26t-8=0

a = 15; b = -26; c = -8;
Δ = b2-4ac
Δ = -262-4·15·(-8)
Δ = 1156
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1156}=34$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-26)-34}{2*15}=\frac{-8}{30}
=-4/15
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-26)+34}{2*15}=\frac{60}{30}
=2
$