4(2+x)=4(2x-1)-8

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Solution for 4(2+x)=4(2x-1)-8 equation: 



4(2+x)=4(2x-1)-8

We move all terms to the left:

4(2+x)-(4(2x-1)-8)=0

We add all the numbers together, and all the variables

4(x+2)-(4(2x-1)-8)=0

We multiply parentheses

4x-(4(2x-1)-8)+8=0



We calculate terms in parentheses: -(4(2x-1)-8), so:

4(2x-1)-8

We multiply parentheses

8x-4-8

We add all the numbers together, and all the variables

8x-12

Back to the equation:

-(8x-12)



We get rid of parentheses

4x-8x+12+8=0

We add all the numbers together, and all the variables

-4x+20=0

We move all terms containing x to the left, all other terms to the right

-4x=-20

x=-20/-4

x=+5

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