3(2y-4)=2(y+5)

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Solution for 3(2y-4)=2(y+5) equation: 



3(2y-4)=2(y+5)

We move all terms to the left:

3(2y-4)-(2(y+5))=0

We multiply parentheses

6y-(2(y+5))-12=0



We calculate terms in parentheses: -(2(y+5)), so:

2(y+5)

We multiply parentheses

2y+10

Back to the equation:

-(2y+10)



We get rid of parentheses

6y-2y-10-12=0

We add all the numbers together, and all the variables

4y-22=0

We move all terms containing y to the left, all other terms to the right

4y=22

y=22/4

y=5+1/2

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