(2x-3)+(3x-4)+(4x-2)=180

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Solution for (2x-3)+(3x-4)+(4x-2)=180 equation: 



(2x-3)+(3x-4)+(4x-2)=180

We move all terms to the left:

(2x-3)+(3x-4)+(4x-2)-(180)=0

We get rid of parentheses

2x+3x+4x-3-4-2-180=0

We add all the numbers together, and all the variables

9x-189=0

We move all terms containing x to the left, all other terms to the right

9x=189

x=189/9

x=21

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