20+3x-12=6x-8-4x

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Solution for 20+3x-12=6x-8-4x equation: 



20+3x-12=6x-8-4x

We move all terms to the left:

20+3x-12-(6x-8-4x)=0

We add all the numbers together, and all the variables

3x-(2x-8)+20-12=0

We add all the numbers together, and all the variables

3x-(2x-8)+8=0

We get rid of parentheses

3x-2x+8+8=0

We add all the numbers together, and all the variables

x+16=0

We move all terms containing x to the left, all other terms to the right

x=-16

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