(4r+4)=(5r-2)

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Solution for (4r+4)=(5r-2) equation: 



(4r+4)=(5r-2)

We move all terms to the left:

(4r+4)-((5r-2))=0

We get rid of parentheses

4r-((5r-2))+4=0



We calculate terms in parentheses: -((5r-2)), so:

(5r-2)

We get rid of parentheses

5r-2

Back to the equation:

-(5r-2)



We get rid of parentheses

4r-5r+2+4=0

We add all the numbers together, and all the variables

-1r+6=0

We move all terms containing r to the left, all other terms to the right

-r=-6

r=-6/-1

r=+6

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