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3(2x-1)3x=-4x+11
We move all terms to the left:
3(2x-1)3x-(-4x+11)=0
We multiply parentheses
18x^2-9x-(-4x+11)=0
We get rid of parentheses
18x^2-9x+4x-11=0
We add all the numbers together, and all the variables
18x^2-5x-11=0
a = 18; b = -5; c = -11;
Δ = b2-4ac
Δ = -52-4·18·(-11)
Δ = 817
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-\sqrt{817}}{2*18}=\frac{5-\sqrt{817}}{36} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+\sqrt{817}}{2*18}=\frac{5+\sqrt{817}}{36} $
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