(4x-4)+(3x-10)+(x+2)=180

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Solution for (4x-4)+(3x-10)+(x+2)=180 equation:



(4x-4)+(3x-10)+(x+2)=180
We move all terms to the left:
(4x-4)+(3x-10)+(x+2)-(180)=0
We get rid of parentheses
4x+3x+x-4-10+2-180=0
We add all the numbers together, and all the variables
8x-192=0
We move all terms containing x to the left, all other terms to the right
8x=192
x=192/8
x=24

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