1=-1/8(-2)+b

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Solution for 1=-1/8(-2)+b equation: 



1=-1/8(-2)+b

We move all terms to the left:

1-(-1/8(-2)+b)=0



Domain of the equation: 8(-2)+b)!=0

b∈R



We multiply all the terms by the denominator


-(-1+1*8(-2)+b)=0



We calculate terms in parentheses: -(-1+1*8(-2)+b), so:

-1+1*8(-2)+b

determiningTheFunctionDomain
b-1+1*8(-2)

We add all the numbers together, and all the variables

b-17

Back to the equation:

-(b-17)



We get rid of parentheses

-b+17=0

We add all the numbers together, and all the variables

-1b+17=0

We move all terms containing b to the left, all other terms to the right

-b=-17

b=-17/-1

b=+17

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