3(2x+5)-4(3x+1)=19

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Solution for 3(2x+5)-4(3x+1)=19 equation: 



3(2x+5)-4(3x+1)=19

We move all terms to the left:

3(2x+5)-4(3x+1)-(19)=0

We multiply parentheses

6x-12x+15-4-19=0

We add all the numbers together, and all the variables

-6x-8=0

We move all terms containing x to the left, all other terms to the right

-6x=8

x=8/-6

x=-1+1/3

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