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6/7x-8=6/4x
We move all terms to the left:
6/7x-8-(6/4x)=0
Domain of the equation: 7x!=0
x!=0/7
x!=0
x∈R
Domain of the equation: 4x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
6/7x-(+6/4x)-8=0
We get rid of parentheses
6/7x-6/4x-8=0
We calculate fractions
24x/28x^2+(-42x)/28x^2-8=0
We multiply all the terms by the denominator
24x+(-42x)-8*28x^2=0
Wy multiply elements
-224x^2+24x+(-42x)=0
We get rid of parentheses
-224x^2+24x-42x=0
We add all the numbers together, and all the variables
-224x^2-18x=0
a = -224; b = -18; c = 0;
Δ = b2-4ac
Δ = -182-4·(-224)·0
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{324}=18$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-18)-18}{2*-224}=\frac{0}{-448} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-18)+18}{2*-224}=\frac{36}{-448} =-9/112 $
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