3(2x+1)=7(1+x)

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Solution for 3(2x+1)=7(1+x) equation: 



3(2x+1)=7(1+x)

We move all terms to the left:

3(2x+1)-(7(1+x))=0

We add all the numbers together, and all the variables

3(2x+1)-(7(x+1))=0

We multiply parentheses

6x-(7(x+1))+3=0



We calculate terms in parentheses: -(7(x+1)), so:

7(x+1)

We multiply parentheses

7x+7

Back to the equation:

-(7x+7)



We get rid of parentheses

6x-7x-7+3=0

We add all the numbers together, and all the variables

-1x-4=0

We move all terms containing x to the left, all other terms to the right

-x=4

x=4/-1

x=-4

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