4(2y+12)=20

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Solution for 4(2y+12)=20 equation: 



4(2y+12)=20

We move all terms to the left:

4(2y+12)-(20)=0

We multiply parentheses

8y+48-20=0

We add all the numbers together, and all the variables

8y+28=0

We move all terms containing y to the left, all other terms to the right

8y=-28

y=-28/8

y=-3+1/2

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