-3y+12=3(2y+5)

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Solution for -3y+12=3(2y+5) equation: 



-3y+12=3(2y+5)

We move all terms to the left:

-3y+12-(3(2y+5))=0



We calculate terms in parentheses: -(3(2y+5)), so:

3(2y+5)

We multiply parentheses

6y+15

Back to the equation:

-(6y+15)



We get rid of parentheses

-3y-6y-15+12=0

We add all the numbers together, and all the variables

-9y-3=0

We move all terms containing y to the left, all other terms to the right

-9y=3

y=3/-9

y=-1/3

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