1/2(2c+20)=2(3c-5)

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Solution for 1/2(2c+20)=2(3c-5) equation: 



1/2(2c+20)=2(3c-5)

We move all terms to the left:

1/2(2c+20)-(2(3c-5))=0



Domain of the equation: 2(2c+20)!=0

c∈R



We multiply all the terms by the denominator


-((2(3c-5)))*2(2c+20)+1=0



We calculate terms in parentheses: -((2(3c-5)))*2(2c+20), so:

(2(3c-5)))*2(2c+20





We calculate terms in parentheses: -((2(3c-5)))*2(2c+20), so:

(2(3c-5)))*2(2c+20





We calculate terms in parentheses: -((2(3c-5)))*2(2c+20), so:

(2(3c-5)))*2(2c+20





We calculate terms in parentheses: -((2(3c-5)))*2(2c+20), so:

(2(3c-5)))*2(2c+20





We calculate terms in parentheses: -((2(3c-5)))*2(2c+20), so:

(2(3c-5)))*2(2c+20





We calculate terms in parentheses: -((2(3c-5)))*2(2c+20), so:

(2(3c-5)))*2(2c+20





We calculate terms in parentheses: -((2(3c-5)))*2(2c+20), so:

(2(3c-5)))*2(2c+20





We calculate terms in parentheses: -((2(3c-5)))*2(2c+20), so:

(2(3c-5)))*2(2c+20





We calculate terms in parentheses: -((2(3c-5)))*2(2c+20), so:

(2(3c-5)))*2(2c+20





We calculate terms in parentheses: -((2(3c-5)))*2(2c+20), so:

(2(3c-5)))*2(2c+20





We calculate terms in parentheses: -((2(3c-5)))*2(2c+20), so:

(2(3c-5)))*2(2c+20





We calculate terms in parentheses: -((2(3c-5)))*2(2c+20), so:

(2(3c-5)))*2(2c+20





We calculate terms in parentheses: -((2(3c-5)))*2(2c+20), so:

(2(3c-5)))*2(2c+20





We calculate terms in parentheses: -((2(3c-5)))*2(2c+20), so:

(2(3c-5)))*2(2c+20





We calculate terms in parentheses: -((2(3c-5)))*2(2c+20), so:

(2(3c-5)))*2(2c+20





We calculate terms in parentheses: -((2(3c-5)))*2(2c+20), so:

(2(3c-5)))*2(2c+20





We calculate terms in parentheses: -((2(3c-5)))*2(2c+20), so:

(2(3c-5)))*2(2c+20





We calculate terms in parentheses: -((2(3c-5)))*2(2c+20), so:

(2(3c-5)))*2(2c+20





We calculate terms in parentheses: -((2(3c-5)))*2(2c+20), so:

(2(3c-5)))*2(2c+20





We calculate terms in parentheses: -((2(3c-5)))*2(2c+20), so:

(2(3c-5)))*2(2c+20





We calculate terms in parentheses: -((2(3c-5)))*2(2c+20), so:

(2(3c-5)))*2(2c+20





We calculate terms in parentheses: -((2(3c-5)))*2(2c+20), so:

(2(3c-5)))*2(2c+20





We calculate terms in parentheses: -((2(3c-5)))*2(2c+20), so:

(2(3c-5)))*2(2c+20





We calculate terms in parentheses: -((2(3c-5)))*2(2c+20), so:

(2(3c-5)))*2(2c+20





We calculate terms in parentheses: -((2(3c-5)))*2(2c+20), so:

(2(3c-5)))*2(2c+20





We calculate terms in parentheses: -((2(3c-5)))*2(2c+20), so:

(2(3c-5)))*2(2c+20





We calculate terms in parentheses: -((2(3c-5)))*2(2c+20), so:

(2(3c-5)))*2(2c+20





We calculate terms in parentheses: -((2(3c-5)))*2(2c+20), so:

(2(3c-5)))*2(2c+20





We calculate terms in parentheses: -((2(3c-5)))*2(2c+20), so:

(2(3c-5)))*2(2c+20





We calculate terms in parentheses: -((2(3c-5)))*2(2c+20), so:

(2(3c-5)))*2(2c+20





We calculate terms in parentheses: -((2(3c-5)))*2(2c+20), so:

(2(3c-5)))*2(2c+20





We calculate terms in parentheses: -((2(3c-5)))*2(2c+20), so:

(2(3c-5)))*2(2c+20





We calculate terms in parentheses: -((2(3c-5)))*2(2c+20), so:

(2(3c-5)))*2(2c+20





We calculate terms in parentheses: -((2(3c-5)))*2(2c+20), so:

(2(3c-5)))*2(2c+20





We calculate terms in parentheses: -((2(3c-5)))*2(2c+20), so:

(2(3c-5)))*2(2c+20





We calculate terms in parentheses: -((2(3c-5)))*2(2c+20), so:

(2(3c-5)))*2(2c+20





We calculate terms in parentheses: -((2(3c-5)))*2(2c+20), so:

(2(3c-5)))*2(2c+20





We calculate terms in parentheses: -((2(3c-5)))*2(2c+20), so:

(2(3c-5)))*2(2c+20





We calculate terms in parentheses: -((2(3c-5)))*2(2c+20), so:

(2(3c-5)))*2(2c+20





We calculate terms in parentheses: -((2(3c-5)))*2(2c+20), so:

(2(3c-5)))*2(2c+20





We calculate terms in parentheses: -((2(3c-5)))*2(2c+20), so:

(2(3c-5)))*2(2c+20





We calculate terms in parentheses: -((2(3c-5)))*2(2c+20), so:

(2(3c-5)))*2(2c+20





We calculate terms in parentheses: -((2(3c-5)))

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