3(2n+1)=8(8n+3)+9

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Solution for 3(2n+1)=8(8n+3)+9 equation: 



3(2n+1)=8(8n+3)+9

We move all terms to the left:

3(2n+1)-(8(8n+3)+9)=0

We multiply parentheses

6n-(8(8n+3)+9)+3=0



We calculate terms in parentheses: -(8(8n+3)+9), so:

8(8n+3)+9

We multiply parentheses

64n+24+9

We add all the numbers together, and all the variables

64n+33

Back to the equation:

-(64n+33)



We get rid of parentheses

6n-64n-33+3=0

We add all the numbers together, and all the variables

-58n-30=0

We move all terms containing n to the left, all other terms to the right

-58n=30

n=30/-58

n=-15/29

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