-3=3/2(-5)+b

Solution for -3=3/2(-5)+b equation:

-3=3/2(-5)+b

We move all terms to the left:

-3-(3/2(-5)+b)=0


Domain of the equation: 2(-5)+b)!=0

b∈R


We multiply all the terms by the denominator


-(3-3*2(-5)+b)=0


We calculate terms in parentheses: -(3-3*2(-5)+b), so:

3-3*2(-5)+b

determiningTheFunctionDomain
b+3-3*2(-5)

We add all the numbers together, and all the variables

b+33

Back to the equation:

-(b+33)


We get rid of parentheses

-b-33=0

We add all the numbers together, and all the variables

-1b-33=0

We move all terms containing b to the left, all other terms to the right

-b=33

b=33/-1

b=-33