(x)=5(x2+1)+16,

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Solution for (x)=5(x2+1)+16, equation: 



(x)=5(x2+1)+16.

We move all terms to the left:

(x)-(5(x2+1)+16.)=0

We add all the numbers together, and all the variables

-(5(+x^2+1)+16.)+x=0



We calculate terms in parentheses: -(5(+x^2+1)+16.), so:

5(+x^2+1)+16.

We add all the numbers together, and all the variables

5(+x^2+1)+16

We multiply parentheses

5x^2+5+16

We add all the numbers together, and all the variables

5x^2+21

Back to the equation:

-(5x^2+21)



We add all the numbers together, and all the variables

x-(5x^2+21)=0

We get rid of parentheses

-5x^2+x-21=0

a = -5; b = 1; c = -21;
Δ = b2-4ac
Δ = 12-4·(-5)·(-21)
Δ = -419
Delta is less than zero, so there is no solution for the equation

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