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2(x-4)-1=6x-4(2+x)
We move all terms to the left:
2(x-4)-1-(6x-4(2+x))=0
We add all the numbers together, and all the variables
2(x-4)-(6x-4(x+2))-1=0
We multiply parentheses
2x-(6x-4(x+2))-8-1=0
We calculate terms in parentheses: -(6x-4(x+2)), so:We add all the numbers together, and all the variables
6x-4(x+2)
We multiply parentheses
6x-4x-8
We add all the numbers together, and all the variables
2x-8
Back to the equation:
-(2x-8)
2x-(2x-8)-9=0
We get rid of parentheses
2x-2x+8-9=0
We add all the numbers together, and all the variables
-1!=0
There is no solution for this equation
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