8(y+5)+y=2(y+3)-8

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Solution for 8(y+5)+y=2(y+3)-8 equation: 



8(y+5)+y=2(y+3)-8

We move all terms to the left:

8(y+5)+y-(2(y+3)-8)=0

We add all the numbers together, and all the variables

y+8(y+5)-(2(y+3)-8)=0

We multiply parentheses

y+8y-(2(y+3)-8)+40=0



We calculate terms in parentheses: -(2(y+3)-8), so:

2(y+3)-8

We multiply parentheses

2y+6-8

We add all the numbers together, and all the variables

2y-2

Back to the equation:

-(2y-2)



We add all the numbers together, and all the variables

9y-(2y-2)+40=0

We get rid of parentheses

9y-2y+2+40=0

We add all the numbers together, and all the variables

7y+42=0

We move all terms containing y to the left, all other terms to the right

7y=-42

y=-42/7

y=-6

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