2z-1+4z+3=52z-1+4(3z-1)

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Solution for 2z-1+4z+3=52z-1+4(3z-1) equation: 



2z-1+4z+3=52z-1+4(3z-1)

We move all terms to the left:

2z-1+4z+3-(52z-1+4(3z-1))=0

We add all the numbers together, and all the variables

6z-(52z-1+4(3z-1))+2=0



We calculate terms in parentheses: -(52z-1+4(3z-1)), so:

52z-1+4(3z-1)

determiningTheFunctionDomain
52z+4(3z-1)-1

We multiply parentheses

52z+12z-4-1

We add all the numbers together, and all the variables

64z-5

Back to the equation:

-(64z-5)



We get rid of parentheses

6z-64z+5+2=0

We add all the numbers together, and all the variables

-58z+7=0

We move all terms containing z to the left, all other terms to the right

-58z=-7

z=-7/-58

z=7/58

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