3(2b-3)+2=2(b+1)+3

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Solution for 3(2b-3)+2=2(b+1)+3 equation: 



3(2b-3)+2=2(b+1)+3

We move all terms to the left:

3(2b-3)+2-(2(b+1)+3)=0

We multiply parentheses

6b-(2(b+1)+3)-9+2=0



We calculate terms in parentheses: -(2(b+1)+3), so:

2(b+1)+3

We multiply parentheses

2b+2+3

We add all the numbers together, and all the variables

2b+5

Back to the equation:

-(2b+5)



We add all the numbers together, and all the variables

6b-(2b+5)-7=0

We get rid of parentheses

6b-2b-5-7=0

We add all the numbers together, and all the variables

4b-12=0

We move all terms containing b to the left, all other terms to the right

4b=12

b=12/4

b=3

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