9(u-1)-5=3(u+2)+4

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Solution for 9(u-1)-5=3(u+2)+4 equation: 



9(u-1)-5=3(u+2)+4

We move all terms to the left:

9(u-1)-5-(3(u+2)+4)=0

We multiply parentheses

9u-(3(u+2)+4)-9-5=0



We calculate terms in parentheses: -(3(u+2)+4), so:

3(u+2)+4

We multiply parentheses

3u+6+4

We add all the numbers together, and all the variables

3u+10

Back to the equation:

-(3u+10)



We add all the numbers together, and all the variables

9u-(3u+10)-14=0

We get rid of parentheses

9u-3u-10-14=0

We add all the numbers together, and all the variables

6u-24=0

We move all terms containing u to the left, all other terms to the right

6u=24

u=24/6

u=4

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