7(r-2)+6=2(r+3)+1

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Solution for 7(r-2)+6=2(r+3)+1 equation: 



7(r-2)+6=2(r+3)+1

We move all terms to the left:

7(r-2)+6-(2(r+3)+1)=0

We multiply parentheses

7r-(2(r+3)+1)-14+6=0



We calculate terms in parentheses: -(2(r+3)+1), so:

2(r+3)+1

We multiply parentheses

2r+6+1

We add all the numbers together, and all the variables

2r+7

Back to the equation:

-(2r+7)



We add all the numbers together, and all the variables

7r-(2r+7)-8=0

We get rid of parentheses

7r-2r-7-8=0

We add all the numbers together, and all the variables

5r-15=0

We move all terms containing r to the left, all other terms to the right

5r=15

r=15/5

r=3

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