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2y/y+3y=4
We move all terms to the left:
2y/y+3y-(4)=0
Domain of the equation: y!=0We add all the numbers together, and all the variables
y∈R
3y+2y/y-4=0
We multiply all the terms by the denominator
3y*y+2y-4*y=0
We add all the numbers together, and all the variables
-2y+3y*y=0
Wy multiply elements
3y^2-2y=0
a = 3; b = -2; c = 0;
Δ = b2-4ac
Δ = -22-4·3·0
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4}=2$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-2}{2*3}=\frac{0}{6} =0 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+2}{2*3}=\frac{4}{6} =2/3 $
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