14y-(6y+4)=3y+5(y-1)+1

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Solution for 14y-(6y+4)=3y+5(y-1)+1 equation: 



14y-(6y+4)=3y+5(y-1)+1

We move all terms to the left:

14y-(6y+4)-(3y+5(y-1)+1)=0

We get rid of parentheses

14y-6y-(3y+5(y-1)+1)-4=0



We calculate terms in parentheses: -(3y+5(y-1)+1), so:

3y+5(y-1)+1

We multiply parentheses

3y+5y-5+1

We add all the numbers together, and all the variables

8y-4

Back to the equation:

-(8y-4)



We add all the numbers together, and all the variables

8y-(8y-4)-4=0

We get rid of parentheses

8y-8y+4-4=0

We add all the numbers together, and all the variables

=0

y=0/1

y=0

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