y-2(y-1)=7-3(y-2)

Solution for y-2(y-1)=7-3(y-2) equation:

y-2(y-1)=7-3(y-2)

We move all terms to the left:

y-2(y-1)-(7-3(y-2))=0

We multiply parentheses

y-2y-(7-3(y-2))+2=0


We calculate terms in parentheses: -(7-3(y-2)), so:

7-3(y-2)

determiningTheFunctionDomain
-3(y-2)+7

We multiply parentheses

-3y+6+7

We add all the numbers together, and all the variables

-3y+13

Back to the equation:

-(-3y+13)


We add all the numbers together, and all the variables

-1y-(-3y+13)+2=0

We get rid of parentheses

-1y+3y-13+2=0

We add all the numbers together, and all the variables

2y-11=0

We move all terms containing y to the left, all other terms to the right

2y=11

y=11/2

y=5+1/2