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(1)/(5x+2)=8
We move all terms to the left:
(1)/(5x+2)-(8)=0
Domain of the equation: (5x+2)!=0We multiply all the terms by the denominator
We move all terms containing x to the left, all other terms to the right
5x!=-2
x!=-2/5
x!=-2/5
x∈R
-8*(5x+2)+1=0
We multiply parentheses
-40x-16+1=0
We add all the numbers together, and all the variables
-40x-15=0
We move all terms containing x to the left, all other terms to the right
-40x=15
x=15/-40
x=-3/8
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