4(4z-6)=+12+4z

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Solution for 4(4z-6)=+12+4z equation: 



4(4z-6)=+12+4z

We move all terms to the left:

4(4z-6)-(+12+4z)=0

We add all the numbers together, and all the variables

4(4z-6)-(4z+12)=0

We multiply parentheses

16z-(4z+12)-24=0

We get rid of parentheses

16z-4z-12-24=0

We add all the numbers together, and all the variables

12z-36=0

We move all terms containing z to the left, all other terms to the right

12z=36

z=36/12

z=3

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