2x-5(x-2)=(-6)+3x-20

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Solution for 2x-5(x-2)=(-6)+3x-20 equation: 



2x-5(x-2)=(-6)+3x-20

We move all terms to the left:

2x-5(x-2)-((-6)+3x-20)=0

We multiply parentheses

2x-5x-((-6)+3x-20)+10=0



We calculate terms in parentheses: -((-6)+3x-20), so:

(-6)+3x-20

determiningTheFunctionDomain
3x-20+(-6)

We add all the numbers together, and all the variables

3x-26

Back to the equation:

-(3x-26)



We add all the numbers together, and all the variables

-3x-(3x-26)+10=0

We get rid of parentheses

-3x-3x+26+10=0

We add all the numbers together, and all the variables

-6x+36=0

We move all terms containing x to the left, all other terms to the right

-6x=-36

x=-36/-6

x=+6

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