2x+7-3(x-9)=2(x+3)+x

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Solution for 2x+7-3(x-9)=2(x+3)+x equation: 



2x+7-3(x-9)=2(x+3)+x

We move all terms to the left:

2x+7-3(x-9)-(2(x+3)+x)=0

We multiply parentheses

2x-3x-(2(x+3)+x)+27+7=0



We calculate terms in parentheses: -(2(x+3)+x), so:

2(x+3)+x

We add all the numbers together, and all the variables

x+2(x+3)

We multiply parentheses

x+2x+6

We add all the numbers together, and all the variables

3x+6

Back to the equation:

-(3x+6)



We add all the numbers together, and all the variables

-1x-(3x+6)+34=0

We get rid of parentheses

-1x-3x-6+34=0

We add all the numbers together, and all the variables

-4x+28=0

We move all terms containing x to the left, all other terms to the right

-4x=-28

x=-28/-4

x=+7

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