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3(5c-3)=3(2c+6)
We move all terms to the left:
3(5c-3)-(3(2c+6))=0
We multiply parentheses
15c-(3(2c+6))-9=0
We calculate terms in parentheses: -(3(2c+6)), so:We get rid of parentheses
3(2c+6)
We multiply parentheses
6c+18
Back to the equation:
-(6c+18)
15c-6c-18-9=0
We add all the numbers together, and all the variables
9c-27=0
We move all terms containing c to the left, all other terms to the right
9c=27
c=27/9
c=3
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