0=5p(4p-3)

Solution for 0=5p(4p-3) equation:

0=5p(4p-3)

We move all terms to the left:

0-(5p(4p-3))=0

We add all the numbers together, and all the variables

-(5p(4p-3))=0


We calculate terms in parentheses: -(5p(4p-3)), so:

5p(4p-3)

We multiply parentheses

20p^2-15p

Back to the equation:

-(20p^2-15p)


We get rid of parentheses

-20p^2+15p=0

a = -20; b = 15; c = 0;
Δ = b2-4ac
Δ = 152-4·(-20)·0
Δ = 225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{225}=15$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-15}{2*-20}=\frac{-30}{-40}
=3/4
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+15}{2*-20}=\frac{0}{-40}
=0
$