5(2f+3)+3(5-3f)=-(4-2f)

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Solution for 5(2f+3)+3(5-3f)=-(4-2f) equation: 



5(2f+3)+3(5-3f)=-(4-2f)

We move all terms to the left:

5(2f+3)+3(5-3f)-(-(4-2f))=0

We add all the numbers together, and all the variables

5(2f+3)+3(-3f+5)-(-(-2f+4))=0

We multiply parentheses

10f-9f-(-(-2f+4))+15+15=0



We calculate terms in parentheses: -(-(-2f+4)), so:

-(-2f+4)

We get rid of parentheses

2f-4

Back to the equation:

-(2f-4)



We add all the numbers together, and all the variables

f-(2f-4)+30=0

We get rid of parentheses

f-2f+4+30=0

We add all the numbers together, and all the variables

-1f+34=0

We move all terms containing f to the left, all other terms to the right

-f=-34

f=-34/-1

f=+34

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