2x+4(3-x)=6(1+2x)

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Solution for 2x+4(3-x)=6(1+2x) equation: 



2x+4(3-x)=6(1+2x)

We move all terms to the left:

2x+4(3-x)-(6(1+2x))=0

We add all the numbers together, and all the variables

2x+4(-1x+3)-(6(2x+1))=0

We multiply parentheses

2x-4x-(6(2x+1))+12=0



We calculate terms in parentheses: -(6(2x+1)), so:

6(2x+1)

We multiply parentheses

12x+6

Back to the equation:

-(12x+6)



We add all the numbers together, and all the variables

-2x-(12x+6)+12=0

We get rid of parentheses

-2x-12x-6+12=0

We add all the numbers together, and all the variables

-14x+6=0

We move all terms containing x to the left, all other terms to the right

-14x=-6

x=-6/-14

x=3/7

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