(3/7)p-1/3=1

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Solution for (3/7)p-1/3=1 equation: 



(3/7)p-1/3=1

We move all terms to the left:

(3/7)p-1/3-(1)=0



Domain of the equation: 7)p!=0

p!=0/1

p!=0

p∈R



determiningTheFunctionDomain
(3/7)p-1-1/3=0

We add all the numbers together, and all the variables

(+3/7)p-1-1/3=0

We multiply parentheses

3p^2-1-1/3=0

We multiply all the terms by the denominator


3p^2*3-1-1*3=0

We add all the numbers together, and all the variables

3p^2*3-4=0

Wy multiply elements

9p^2-4=0

a = 9; b = 0; c = -4;
Δ = b2-4ac
Δ = 02-4·9·(-4)
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{144}=12$


$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-12}{2*9}=\frac{-12}{18}
=-2/3
$


$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+12}{2*9}=\frac{12}{18}
=2/3
$

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