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9(x-4)=3(x+5)
We move all terms to the left:
9(x-4)-(3(x+5))=0
We multiply parentheses
9x-(3(x+5))-36=0
We calculate terms in parentheses: -(3(x+5)), so:We get rid of parentheses
3(x+5)
We multiply parentheses
3x+15
Back to the equation:
-(3x+15)
9x-3x-15-36=0
We add all the numbers together, and all the variables
6x-51=0
We move all terms containing x to the left, all other terms to the right
6x=51
x=51/6
x=8+1/2
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