(7x-12)+(3x+28)=180

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Solution for (7x-12)+(3x+28)=180 equation: 



(7x-12)+(3x+28)=180

We move all terms to the left:

(7x-12)+(3x+28)-(180)=0

We get rid of parentheses

7x+3x-12+28-180=0

We add all the numbers together, and all the variables

10x-164=0

We move all terms containing x to the left, all other terms to the right

10x=164

x=164/10

x=16+2/5

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