4+2(x-3)=3(x+3)+6

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Solution for 4+2(x-3)=3(x+3)+6 equation: 



4+2(x-3)=3(x+3)+6

We move all terms to the left:

4+2(x-3)-(3(x+3)+6)=0

We multiply parentheses

2x-(3(x+3)+6)-6+4=0



We calculate terms in parentheses: -(3(x+3)+6), so:

3(x+3)+6

We multiply parentheses

3x+9+6

We add all the numbers together, and all the variables

3x+15

Back to the equation:

-(3x+15)



We add all the numbers together, and all the variables

2x-(3x+15)-2=0

We get rid of parentheses

2x-3x-15-2=0

We add all the numbers together, and all the variables

-1x-17=0

We move all terms containing x to the left, all other terms to the right

-x=17

x=17/-1

x=-17

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