2x+-19=3(x+-5)

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Solution for 2x+-19=3(x+-5) equation: 



2x+-19=3(x+-5)

We move all terms to the left:

2x+-19-(3(x+-5))=0

We add all the numbers together, and all the variables

2x-(3(x-5))-19+=0

We add all the numbers together, and all the variables

2x-(3(x-5))=0



We calculate terms in parentheses: -(3(x-5)), so:

3(x-5)

We multiply parentheses

3x-15

Back to the equation:

-(3x-15)



We get rid of parentheses

2x-3x+15=0

We add all the numbers together, and all the variables

-1x+15=0

We move all terms containing x to the left, all other terms to the right

-x=-15

x=-15/-1

x=+15

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