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8/3c-2=2/5c-12
We move all terms to the left:
8/3c-2-(2/5c-12)=0
Domain of the equation: 3c!=0
c!=0/3
c!=0
c∈R
Domain of the equation: 5c-12)!=0We get rid of parentheses
c∈R
8/3c-2/5c+12-2=0
We calculate fractions
40c/15c^2+(-6c)/15c^2+12-2=0
We add all the numbers together, and all the variables
40c/15c^2+(-6c)/15c^2+10=0
We multiply all the terms by the denominator
40c+(-6c)+10*15c^2=0
Wy multiply elements
150c^2+40c+(-6c)=0
We get rid of parentheses
150c^2+40c-6c=0
We add all the numbers together, and all the variables
150c^2+34c=0
a = 150; b = 34; c = 0;
Δ = b2-4ac
Δ = 342-4·150·0
Δ = 1156
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1156}=34$$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(34)-34}{2*150}=\frac{-68}{300} =-17/75 $$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(34)+34}{2*150}=\frac{0}{300} =0 $
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