-5(3y+1)-2y=3(y-6)-3

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Solution for -5(3y+1)-2y=3(y-6)-3 equation: 



-5(3y+1)-2y=3(y-6)-3

We move all terms to the left:

-5(3y+1)-2y-(3(y-6)-3)=0

We add all the numbers together, and all the variables

-2y-5(3y+1)-(3(y-6)-3)=0

We multiply parentheses

-2y-15y-(3(y-6)-3)-5=0



We calculate terms in parentheses: -(3(y-6)-3), so:

3(y-6)-3

We multiply parentheses

3y-18-3

We add all the numbers together, and all the variables

3y-21

Back to the equation:

-(3y-21)



We add all the numbers together, and all the variables

-17y-(3y-21)-5=0

We get rid of parentheses

-17y-3y+21-5=0

We add all the numbers together, and all the variables

-20y+16=0

We move all terms containing y to the left, all other terms to the right

-20y=-16

y=-16/-20

y=4/5

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