6=(4+11+z)/3

Solution for 6=(4+11+z)/3 equation:

6=(4+11+z)/3

We move all terms to the left:

6-((4+11+z)/3)=0

We add all the numbers together, and all the variables

-((z+15)/3)+6=0

We multiply all the terms by the denominator


-((z+15)+6*3)=0


We calculate terms in parentheses: -((z+15)+6*3), so:

(z+15)+6*3

We add all the numbers together, and all the variables

(z+15)+18

We get rid of parentheses

z+15+18

We add all the numbers together, and all the variables

z+33

Back to the equation:

-(z+33)


We get rid of parentheses

-z-33=0

We add all the numbers together, and all the variables

-1z-33=0

We move all terms containing z to the left, all other terms to the right

-z=33

z=33/-1

z=-33