2x(x-10)+11=(2x-3)(x+6)

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Solution for 2x(x-10)+11=(2x-3)(x+6) equation: 



2x(x-10)+11=(2x-3)(x+6)

We move all terms to the left:

2x(x-10)+11-((2x-3)(x+6))=0

We multiply parentheses

2x^2-20x-((2x-3)(x+6))+11=0

We multiply parentheses ..

2x^2-((+2x^2+12x-3x-18))-20x+11=0



We calculate terms in parentheses: -((+2x^2+12x-3x-18)), so:

(+2x^2+12x-3x-18)

We get rid of parentheses

2x^2+12x-3x-18

We add all the numbers together, and all the variables

2x^2+9x-18

Back to the equation:

-(2x^2+9x-18)



We add all the numbers together, and all the variables

2x^2-20x-(2x^2+9x-18)+11=0

We get rid of parentheses

2x^2-2x^2-20x-9x+18+11=0

We add all the numbers together, and all the variables

-29x+29=0

We move all terms containing x to the left, all other terms to the right

-29x=-29

x=-29/-29

x=1

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