2/x-4+4/3x-12=16

Solution for 2/x-4+4/3x-12=16 equation:

2/x-4+4/3x-12=16

We move all terms to the left:

2/x-4+4/3x-12-(16)=0


Domain of the equation: x!=0

x∈R



Domain of the equation: 3x!=0

x!=0/3

x!=0

x∈R


We add all the numbers together, and all the variables

2/x+4/3x-32=0

We calculate fractions


6x/3x^2+4x/3x^2-32=0

We multiply all the terms by the denominator


6x+4x-32*3x^2=0

We add all the numbers together, and all the variables

10x-32*3x^2=0

Wy multiply elements

-96x^2+10x=0

a = -96; b = 10; c = 0;
Δ = b2-4ac
Δ = 102-4·(-96)·0
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{100}=10$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-10}{2*-96}=\frac{-20}{-192}
=5/48
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+10}{2*-96}=\frac{0}{-192}
=0
$