78+(4z-2)=180

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Solution for 78+(4z-2)=180 equation: 



78+(4z-2)=180

We move all terms to the left:

78+(4z-2)-(180)=0

We add all the numbers together, and all the variables

(4z-2)-102=0

We get rid of parentheses

4z-2-102=0

We add all the numbers together, and all the variables

4z-104=0

We move all terms containing z to the left, all other terms to the right

4z=104

z=104/4

z=26

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