((3a-2)/7)-((3+2a)/35)=6

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Solution for ((3a-2)/7)-((3+2a)/35)=6 equation:



((3a-2)/7)-((3+2a)/35)=6
We move all terms to the left:
((3a-2)/7)-((3+2a)/35)-(6)=0
We add all the numbers together, and all the variables
((3a-2)/7)-((2a+3)/35)-6=0
We calculate fractions
(105a-70)/()+(-14a-21)/()-6=0
We multiply all the terms by the denominator
(105a-70)+(-14a-21)-6*()=0
We add all the numbers together, and all the variables
(105a-70)+(-14a-21)=0
We get rid of parentheses
105a-14a-70-21=0
We add all the numbers together, and all the variables
91a-91=0
We move all terms containing a to the left, all other terms to the right
91a=91
a=91/91
a=1

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