78=(4z-2)=180

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Solution for 78=(4z-2)=180 equation: 



78=(4z-2)=180

We move all terms to the left:

78-((4z-2))=0



We calculate terms in parentheses: -((4z-2)), so:

(4z-2)

We get rid of parentheses

4z-2

Back to the equation:

-(4z-2)



We get rid of parentheses

-4z+2+78=0

We add all the numbers together, and all the variables

-4z+80=0

We move all terms containing z to the left, all other terms to the right

-4z=-80

z=-80/-4

z=+20

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